A person travels A to B a distance of 200 miles in 5 hours. He returns to A in 4 hours. His average speed is:A)200/9mphB)100/9mphC)150mphD)400/9mph
Question
A person travels A to B a distance of 200 miles in 5 hours. He returns to A in 4 hours. His average speed is:
A) 200/9 mph
B) 100/9 mph
C) 150 mph
D) 400/9 mph
Solution
To solve this problem, we need to find the average speed for the entire journey.
Step 1: Find the speed of each leg of the journey.
- The speed from A to B is distance/time = 200 miles / 5 hours = 40 mph.
- The speed from B to A is distance/time = 200 miles / 4 hours = 50 mph.
Step 2: Find the total distance and total time.
- The total distance is 200 miles (A to B) + 200 miles (B to A) = 400 miles.
- The total time is 5 hours (A to B) + 4 hours (B to A) = 9 hours.
Step 3: Calculate the average speed.
- The average speed is total distance / total time = 400 miles / 9 hours = 44.44 mph.
So, the answer closest to this is D) 400/9 mph.
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