The equation you've provided seems to have a typo. It's not clear where the "minus 33x" fits in. However, if the equation is 3x^2 + 16x + 1 = 9x - 3, here's how you would solve it:

Step 1: Rearrange the equation to set it equal to zero.

3x^2 + 16x - 9x + 1 + 3 = 0

This simplifies to:

3x^2 + 7x + 4 = 0

Step 2: Factor the quadratic equation.

This equation can be factored into:

(3x + 4)(x + 1) = 0

Step 3: Set each factor equal to zero and solve for x.

3x + 4 = 0 -- 3x = -4 -- x = -4/3

x + 1 = 0 -- x = -1

So, the solutions to the equation are x = -4/3 and x = -1.

Question

The equation you've provided seems to have a typo. It's not clear where the "minus 33x" fits in. However, if the equation is 3x^2 + 16x + 1 = 9x - 3, here's how you would solve it:

Step 1: Rearrange the equation to set it equal to zero.

3x^2 + 16x - 9x + 1 + 3 = 0

This simplifies to:

3x^2 + 7x + 4 = 0

Step 2: Factor the quadratic equation.

This equation can be factored into:

(3x + 4)(x + 1) = 0

Step 3: Set each factor equal to zero and solve for x.

3x + 4 = 0  --> 3x = -4  --> x = -4/3

x + 1 = 0  --> x = -1

So, the solutions to the equation are x = -4/3 and x = -1.

Knowee AI · Accepted Answer

The equation you've provided seems to have a typo. It's not clear where the "minus 33x" fits in. However, if the equation is 3x^2 + 16x + 1 = 9x - 3, here's how you would solve it:

Step 1: Rearrange the equation to set it equal to zero.

3x^2 + 16x - 9x + 1 + 3 = 0

This simplifies to:

3x^2 + 7x + 4 = 0

Step 2: Factor the quadratic equation.

This equation can be factored into:

(3x + 4)(x + 1) = 0

Step 3: Set each factor equal to zero and solve for x.

3x + 4 = 0  --> 3x = -4  --> x = -4/3

x + 1 = 0  --> x = -1

So, the solutions to the equation are x = -4/3 and x = -1.

Solve the quadratic by factoring.3, x, squared, plus, 16, x, plus, 1, equals, 9, x, minus, 33x 2 +16x+1=9x−3

Question

Solve the quadratic by factoring.

Solution

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