To determine the output of the provided Python code, let's analyze it step by step.

### Breakdown of the Problem
1. The function `call(var)` is defined to take one argument called `var`.
2. Inside the function, the `print` function is called with the argument `var` and the `end` parameter set to an empty string (`''`), which means it won't add a newline after printing.
3. The function is then called with the argument `45`.

### Relevant Concepts
- `print()` function in Python: The `print` function outputs data to the console. The `end` parameter modifies what is printed at the end of the output; by default, it is a newline character (`
`).
- Function call: When `call(45)` is executed, the value `45` will be passed to the `var` parameter.

### Analysis and Detail
1. The argument `45` is passed to the function `call`.
2. Inside the function, the `print(var, end='')` statement will print `45` without adding a newline afterwards.

### Verify and Summarize
- Since the function is called only once with the value `45`, the output will simply be `45` printed directly to the console without any additional characters or newline after it.

### Final Answer
The output of the given code will be:
```
45
```

Question

To determine the output of the provided Python code, let's analyze it step by step.

### Breakdown of the Problem
1. The function `call(var)` is defined to take one argument called `var`.
2. Inside the function, the `print` function is called with the argument `var` and the `end` parameter set to an empty string (`''`), which means it won't add a newline after printing.
3. The function is then called with the argument `45`.

### Relevant Concepts
- `print()` function in Python: The `print` function outputs data to the console. The `end` parameter modifies what is printed at the end of the output; by default, it is a newline character (`
`).
- Function call: When `call(45)` is executed, the value `45` will be passed to the `var` parameter.

### Analysis and Detail
1. The argument `45` is passed to the function `call`.
2. Inside the function, the `print(var, end='')` statement will print `45` without adding a newline afterwards.

### Verify and Summarize
- Since the function is called only once with the value `45`, the output will simply be `45` printed directly to the console without any additional characters or newline after it.

### Final Answer
The output of the given code will be:
```
45
```

Knowee AI · Accepted Answer

To determine the output of the provided Python code, let's analyze it step by step.

### Breakdown of the Problem
1. The function `call(var)` is defined to take one argument called `var`.
2. Inside the function, the `print` function is called with the argument `var` and the `end` parameter set to an empty string (`''`), which means it won't add a newline after printing.
3. The function is then called with the argument `45`.

### Relevant Concepts
- `print()` function in Python: The `print` function outputs data to the console. The `end` parameter modifies what is printed at the end of the output; by default, it is a newline character (`
`).
- Function call: When `call(45)` is executed, the value `45` will be passed to the `var` parameter.

### Analysis and Detail
1. The argument `45` is passed to the function `call`.
2. Inside the function, the `print(var, end='')` statement will print `45` without adding a newline afterwards.

### Verify and Summarize
- Since the function is called only once with the value `45`, the output will simply be `45` printed directly to the console without any additional characters or newline after it.

### Final Answer
The output of the given code will be:
```
45
```

What will be the output after the following statements?def call(var) : print(var, end ='') call(45)Options5545var4 5

Question

What will be the output after the following statements?

Solution

Breakdown of the Problem

Relevant Concepts

Analysis and Detail

Verify and Summarize

Final Answer

Similar Questions

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