Select the correct answerWhat will be the output of the following Python code?def ct(y): global y y+=2 print(y)ct(5)print("hi")Optionserror77hihi
Question
Select the correct answer
What will be the output of the following Python code?
def ct(y):
global y
y+=2
print(y)
ct(5)
print("hi")
Options:
- error
- 77
- hi
- hi
Solution
Break Down the Problem
- Identify the Code Components:
- Function definition (
def ct(y)
) with a global variabley
. - Incrementing the global variable
y
by 2. - Printing the value of
y
. - Calling the function
ct(5)
. - Printing the string "hi".
- Function definition (
Relevant Concepts
- Understanding Global Variables:
- The
global
keyword allows the function to modify the variable defined outside its scope. - The function
ct
expects an argument (y
), which is local to the function.
- The
Analysis and Detail
- Execution Steps:
- When
ct(5)
is called:y
is treated as a global variable initially undefined.- The argument passed (5) is assigned to the local parameter
y
.
- The statement
y += 2
attempts to increment the undefined globaly
by 2. - Since the global
y
has not been initialized, this results in anUnboundLocalError
, indicating that the local variabley
refers to the global variabley
which has not been assigned a value yet.
- When
Verify and Summarize
- Error Encountered:
- The code will raise an UnboundLocalError since
y
is referenced before being assigned a value globally.
- The code will raise an UnboundLocalError since
Final Answer
The output of the code will be an error: UnboundLocalError.
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