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A man drives his motorcycle horizontally off the end of a cliff and lands in the water 2 s later. How high is the cliff?

Question

A man drives his motorcycle horizontally off the end of a cliff and lands in the water 2 s later. How high is the cliff?

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Solution

Sure, to solve this problem, we need to use the formula for the distance travelled under constant acceleration, which in this case is due to gravity. The formula is:

d = v_it + 0.5a*t^2

where:

  • d is the distance travelled (which is the height of the cliff in this case),
  • v_i is the initial velocity (which is 0 in this case because the man is falling straight down),
  • a is the acceleration (which is the acceleration due to gravity, approximately 9.8 m/s^2), and
  • t is the time (which is 2 seconds in this case).

Substituting the known values into the formula, we get:

d = 02 + 0.59.8*2^2

Solving this equation gives:

d = 0 + 0.59.84 = 19.6 meters

So, the cliff is approximately 19.6 meters high.

This problem has been solved

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