When the stone hits the ground, its height is 0 ft. We can now use0 = s(4.75) = −16 2  + h.Solving for h we find that the height of the cliff ish = ft.

It seems like you're trying to solve for the initial height (h) of a stone thrown off a cliff using the equation for the height of an object in free fall: 0 = -16(4.75)^2 + h. This equation is derived from the physics formula for the height of an object under the influence of gravity, which is h = -16t^2 + vt + h0, where t is the time, v is the initial velocity, and h0 is the initial height. In this case, the stone is dropped (so initial velocity, v, is 0) and it hits the ground after 4.75 seconds (so final height, h, is 0).

Here's how you can solve for h:

1. Substitute the given values into the equation: 0 = -16(4.75)^2 + h
2. Simplify the equation: 0 = -16*22.5625 + h
3. Simplify further: 0 = -360.25 + h
4. Solve for h by adding 360.25 to both sides of the equation: h = 360.25 feet

So, the height of the cliff is approximately 360.25 feet.