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find the equation of the line that passes through the point (-9,-8) and has slope 1/3.Simplify your equation to the following form.y=1/3x+

Question

Find the equation of the line that passes through the point (-9,-8) and has slope 13 \frac{1}{3} . Simplify your equation to the following form:

y=13x+ y = \frac{1}{3}x +

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Solution

The equation of a line is given by the formula y = mx + b, where m is the slope and b is the y-intercept.

We know that the slope (m) is 1/3 and the line passes through the point (-9,-8). We can substitute these values into the equation to find the y-intercept (b).

-8 = (1/3)(-9) + b -8 = -3 + b b = -8 + 3 b = -5

So, the equation of the line is y = 1/3x - 5.

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1/3

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