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find the equation of the line that passes through the point (-8,-4)and has slope -7/4. simplify your equation to the following form. y=-7/4x+

Question

Find the equation of the line that passes through the point (-8,-4) and has slope -7/4. Simplify your equation to the following form.

y=74x+? y = -\frac{7}{4}x + \text{?}

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Solution

The equation of a line in slope-intercept form is given by y = mx + b, where m is the slope and b is the y-intercept.

Given that the slope (m) is -7/4 and the line passes through the point (-8,-4), we can substitute these values into the equation to find the y-intercept (b).

-4 = (-7/4)(-8) + b -4 = 14 + b b = -4 - 14 b = -18

So, the equation of the line is y = -7/4x - 18.

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