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The following is a Poisson probability distribution with µ = 0.2. x P(x)0 0.90421 0.08902 0.00603 0.0008The variance of the distribution is ______.

Question

The following is a Poisson probability distribution with µ = 0.2.

x P(x)
0 0.90421
1 0.08902
2 0.00603
3 0.0008

The variance of the distribution is ______.

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Solution

1. ### Break Down the Problem

To find the variance of a Poisson distribution, we need to understand that for a Poisson distribution, the variance is equal to the mean μ \mu .

2. ### Relevant Concepts

For a Poisson distribution:

  • Mean μ \mu
  • Variance σ2=μ \sigma^2 = \mu

Given μ=0.2 \mu = 0.2 .

3. ### Analysis and Detail

Since the variance and mean are equal in a Poisson distribution:

  • Variance σ2=0.2 \sigma^2 = 0.2

4. ### Verify and Summarize

The calculations confirm that for a Poisson distribution, the variance is indeed equal to the mean. Therefore, the variance of the distribution is 0.2.

Final Answer

The variance of the distribution is 0.2 0.2 .

This problem has been solved

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