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The driving-point impedance Z(s) of a network has the pole-zero locations as shown. If Z(0) = 3, then Z(s) is

Question

The driving-point impedance Z(s) of a network has the pole-zero locations as shown. If Z(0) = 3, then Z(s) is

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Solution

To find the driving-point impedance Z(s) Z(s) of the network based on the given pole-zero locations and the condition Z(0)=3 Z(0) = 3 , we can follow these steps:

1. ### Break Down the Problem

  1. Identify the pole and zero locations.
  2. Use the pole-zero information to formulate the impedance function.
  3. Apply the condition Z(0)=3 Z(0) = 3 to determine any constants.

2. ### Relevant Concepts

  • The general form of a driving-point impedance can be represented as: Z(s)=K(sz1)(sz2)(szm)(sp1)(sp2)(spn) Z(s) = K \frac{(s-z_1)(s-z_2)\ldots(s-z_m)}{(s-p_1)(s-p_2)\ldots(s-p_n)} where K K is a constant, zi z_i are the zeros, and pj p_j are the poles.

3. ### Analysis and Detail

Assuming the specific pole-zero locations were provided (but not explicitly stated here), we would substitute those into the formula. For example, let’s say we have:

  • Zeros at z1 z_1 and z2 z_2
  • Poles at p1 p_1 and p2 p_2

Then, the impedance function can be written as: Z(s)=K(sz1)(sz2)(sp1)(sp2) Z(s) = K \frac{(s - z_1)(s - z_2)}{(s - p_1)(s - p_2)}

Now, we need to apply the condition Z(0)=3 Z(0) = 3 : Z(0)=K(z1)(z2)(p1)(p2)=Kz1z2p1p2 Z(0) = K \frac{(-z_1)(-z_2)}{(-p_1)(-p_2)} = K \frac{z_1 z_2}{p_1 p_2} Setting this equal to 3: Kz1z2p1p2=3 K \frac{z_1 z_2}{p_1 p_2} = 3

4. ### Verify and Summarize

By isolating K K : K=3p1p2z1z2 K = \frac{3 p_1 p_2}{z_1 z_2}

With all values for zeros and poles identified, we could write out the final expression for Z(s) Z(s) .

Final Answer

Thus, the final impedance function Z(s) Z(s) can be expressed as: Z(s)=(3p1p2z1z2)(sz1)(sz2)(sp1)(sp2) Z(s) = \left( \frac{3 p_1 p_2}{z_1 z_2} \right) \frac{(s - z_1)(s - z_2)}{(s - p_1)(s - p_2)}

Make sure to provide the specific pole and zero values to finalize the equation.

This problem has been solved

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