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Study the following program:i = 0while i < 3:       print(i)       i += 1 else:      print(0)

Question

Study the following program:

	i = 0
while i &lt; 3: 
    print(i) 
    i += 1 
else:
    print(0)
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Solution

This is a simple Python program that uses a while loop to print numbers. Here's a step-by-step explanation:

  1. The variable i is initialized with the value 0.

  2. The while loop checks if the value of i is less than 3. If it is, it enters the loop.

  3. Inside the loop, it first prints the current value of i.

  4. Then, it increments the value of i by 1 using the += operator.

  5. The loop then goes back to step 2, checking the condition again. If i is still less than 3, it repeats steps 3 and 4.

  6. This continues until i is no longer less than 3 (i.e., when i is 3), at which point it exits the loop.

  7. After the loop, the else clause is executed, which prints 0.

So, the output of this program would be:

0
1
2
0

This problem has been solved

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1/3

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