The program will result in an error because the variable 'i' is not defined before the while loop.

However, if we assume that 'i' is defined and its initial value is 0, then the program will print numbers from 0 to 19. Each number will be printed on a new line. The loop will stop when 'i' becomes 20 because 20 is not less than 20.

Here is the corrected code:

```python
i = 0
while i

Question

The program will result in an error because the variable 'i' is not defined before the while loop.

However, if we assume that 'i' is defined and its initial value is 0, then the program will print numbers from 0 to 19. Each number will be printed on a new line. The loop will stop when 'i' becomes 20 because 20 is not less than 20.

Here is the corrected code:

```python
i = 0
while i < 20:
  print(i)
  i += 1
```

And here is the output:

```python
0
1
2
3
4
5
6
7
8
9
10
11
12
13
14
15
16
17
18
19
```

Knowee AI · Accepted Answer

The program will result in an error because the variable 'i' is not defined before the while loop.

However, if we assume that 'i' is defined and its initial value is 0, then the program will print numbers from 0 to 19. Each number will be printed on a new line. The loop will stop when 'i' becomes 20 because 20 is not less than 20.

Here is the corrected code:

```python
i = 0
while i < 20:
  print(i)
  i += 1
```

And here is the output:

```python
0
1
2
3
4
5
6
7
8
9
10
11
12
13
14
15
16
17
18
19
```

What will be the output of the following program?while i < 20: print(i) i += 1

Question

What will be the output of the following program?

Solution

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