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Some points on this line are:x 0 1 2 3y –1 1 3 5The equation for this straight line is y = 2x – 1.Another way to write this equation is:

Question

Some points on this line are:

x 0 1 2 3
y -1 1 3 5

The equation for this straight line is y = 2x - 1. Another way to write this equation is:

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Solution

The equation of the line can be expressed in several different forms. The standard forms to express a linear equation are:

  1. Slope-Intercept Form: This is the form already given, which is y=mx+b y = mx + b , where m m is the slope and b b is the y-intercept.
  2. Point-Slope Form: This form is useful for writing the equation of a line when you know a point on the line and its slope, represented as yy1=m(xx1) y - y_1 = m(x - x_1) .
  3. Standard Form: This is another way to present the equation, often in the format Ax+By=C Ax + By = C , where A A , B B , and C C are integers.

Another Way to Write the Equation y=2x1 y = 2x - 1

  1. Point-Slope Form: To transform to point-slope form using a point on the line, take the point (0,1) (0, -1) (when x=0 x = 0 , y=1 y = -1 ): y(1)=2(x0)    y+1=2x y - (-1) = 2(x - 0) \implies y + 1 = 2x

  2. Standard Form: Rearranging the slope-intercept form to standard form: 2xy=1 2x - y = 1

Final Answer

The equation for the line can also be written in point-slope form as y+1=2x y + 1 = 2x or in standard form as 2xy=1 2x - y = 1 .

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