Two APs have the same common difference. The first term of one of these is –1 andthat of the other is – 8. Then the difference between their 4th terms is
Question
Two APs have the same common difference. The first term of one of these is –1 and that of the other is – 8. Then the difference between their 4th terms is
Solution
To find the difference between the 4th terms of two arithmetic progressions (APs) with the same common difference, we need to determine the terms of each AP.
Let's denote the common difference as 'd'. The first term of one AP is -1, so the terms of this AP would be: 1st term: -1 2nd term: -1 + d 3rd term: -1 + 2d 4th term: -1 + 3d
Similarly, the first term of the other AP is -8, so the terms of this AP would be: 1st term: -8 2nd term: -8 + d 3rd term: -8 + 2d 4th term: -8 + 3d
Now, we can find the difference between their 4th terms by subtracting the 4th term of the second AP from the 4th term of the first AP: (-1 + 3d) - (-8 + 3d) Simplifying this expression, we get: -1 + 3d + 8 - 3d Combining like terms, we have: 7
Therefore, the difference between the 4th terms of the two APs is 7.
Similar Questions
The first four terms of an AP, whose first term is –2 and the common difference is –2, are
If the third and the ninth terms of an AP are 4 and -8 respectively, which term of this AP is zer
. How many terms are there in an AP whose first and fifth terms are - 14 and 2 respectively and the last term is 62.
If the common difference of an AP is 5, then find the value of below mentioned expression.
What is the common difference of the A.P in which 18th term – 14th term = 32? *8-84-4
Upgrade your grade with Knowee
Get personalized homework help. Review tough concepts in more detail, or go deeper into your topic by exploring other relevant questions.