. How many terms are there in an AP whose first and fifth terms are - 14 and 2 respectively and the last term is 62.
Question
How many terms are there in an AP whose first and fifth terms are - 14 and 2 respectively and the last term is 62?
Solution
To find the number of terms in an Arithmetic Progression (AP), we first need to find the common difference (d).
Step 1: Find the common difference The common difference (d) can be found using the formula: d = (a5 - a1) / (5 - 1), where a5 is the fifth term and a1 is the first term.
Substituting the given values, we get: d = (2 - (-14)) / (5 - 1) = 16 / 4 = 4.
Step 2: Find the number of terms The formula to find the nth term (an) of an AP is: an = a1 + (n - 1) * d, where a1 is the first term, n is the number of terms, and d is the common difference.
We know that the last term (an) is 62, a1 is -14, and d is 4. Substituting these values into the formula, we get: 62 = -14 + (n - 1) * 4.
Solving this equation for n, we get: n = (62 + 14) / 4 + 1 = 76 / 4 + 1 = 19 + 1 = 20.
So, there are 20 terms in the given AP.
Similar Questions
An AP consists of 50 terms of which 3rd term is 12 and the last term is 106. Find the 29thterm
If the third and the ninth terms of an AP are 4 and -8 respectively, which term of this AP is zer
The first four terms of an AP, whose first term is –2 and the common difference is –2, are
Two APs have the same common difference. The first term of one of these is –1 andthat of the other is – 8. Then the difference between their 4th terms is
The sum of 4th and 8th terms of an A.P. is 24 and the sum of the 6th and 10th terms is 34. The First term is:
Upgrade your grade with Knowee
Get personalized homework help. Review tough concepts in more detail, or go deeper into your topic by exploring other relevant questions.