The multiplication of Kishan’s age before 3 years and after 6 years is 486. Find out the average of 5 years back age and age of Kishan after 5 years.

Let's denote Kishan's current age as x.

According to the problem, Kishan's age 3 years ago (x-3) multiplied by his age 6 years from now (x+6) equals 486. This gives us the equation:

(x-3)(x+6) = 486

Expanding this equation gives:

x^2 + 3x - 18 = 486

Subtract 486 from both sides to set the equation to zero:

x^2 + 3x - 504 = 0

This is a quadratic equation in the form ax^2 + bx + c = 0. We can solve it by factoring, completing the square, or using the quadratic formula. In this case, factoring is the simplest method:

(x - 21)(x + 24) = 0

Setting each factor equal to zero gives the solutions x = 21 and x = -24. Since age cannot be negative, we discard x = -24. So, Kishan's current age is 21 years.

Now, we need to find the average of Kishan's age 5 years ago and his age 5 years from now. Five years ago, Kishan was 21 - 5 = 16 years old. Five years from now, he will be 21 + 5 = 26 years old.

The average of these two ages is:

(16 + 26) / 2 = 21

So, the average of Kishan's age 5 years ago and his age 5 years from now is 21 years.