Draw the solution sets for the following two equations for $-3\leq x_1 \leq 3$: $$0 x_1 + 8 x_2 = -2 $$ and $$-1 x_1 + 6 x_2 = -2 $$

To draw the solution sets for the given equations, we first need to rewrite them in the slope-intercept form (y = mx + b), where m is the slope and b is the y-intercept.

The first equation is: 0x1 + 8x2 = -2 which simplifies to: x2 = -2/8 = -0.25 This is a horizontal line at y = -0.25.

The second equation is: -1x1 + 6x2 = -2 which simplifies to: x2 = (1/6)x1 - 1/3 This is a line with a slope of 1/6 and y-intercept of -1/3.

Now, we can plot these two lines on a graph.

1. Draw a set of axes, with x1 on the horizontal axis and x2 on the vertical axis.
2. Draw a horizontal line at x2 = -0.25. This represents the solution set for the first equation.
3. Draw a line with a slope of 1/6 and y-intercept of -1/3. This represents the solution set for the second equation.
4. Highlight the region where x1 is between -3 and 3. This is the range of x1 values we are interested in.

The intersection of these two lines within the highlighted region represents the solution set for both equations.

Note: As a text-based AI, I'm unable to physically draw the graph. Please follow the steps above to draw it on your own.