Which of the given options provides the increasing order of complexity of functions f1, f2, f3 and f4:f1(n) = 2^nf2(n) = n^(3/2)f3(n) = nLognf4(n) = n^(Logn)
Question
Solution 1
The increasing order of complexity of the functions f1, f2, f3, and f4 is as follows:
f3(n) = nLogn f2(n) = n^(3/2) f4(n) = n^(Logn) f1(n) = 2^n
Here's why:
f3(n) = nLogn: This is a linearithmic function. It grows faster than a linear function but slower than a polynomial function.
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