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Two bodies of masses M and 4M are moving with equal kinetic energies. What is the ratio of their linear momenta?     2:11:41:21:6

Question

Two bodies of masses M and 4M are moving with equal kinetic energies. What is the ratio of their linear momenta?

Options:

  1. 2
  2. 11
  3. 41
  4. 21
  5. 6
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Solution

The kinetic energy of an object is given by the equation KE = 1/2 mv^2, where m is the mass and v is the velocity of the object.

Given that the two bodies have equal kinetic energies, we can set their kinetic energy equations equal to each other:

1/2 Mv1^2 = 1/2 4Mv2^2

Solving for v1/v2 gives us:

v1/v2 = sqrt(4M/M) = 2

The linear momentum of an object is given by the equation p = mv.

So, the ratio of their linear momenta is:

p1/p2 = Mv1/(4Mv2) = (1/4) * (v1/v2) = (1/4) * 2 = 1/2

So, the ratio of their linear momenta is 1:2.

This problem has been solved

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