Two bodies A and B having masses in the ratio of 3 : 1 possess the same kinetic energy. The ratio of linear momentum of B to A is :
Question
Solution 1
Let the masses of bodies A and B be represented by m_A and m_B respectively. Given that the masses are in the ratio of 3:1, we can write m_A/m_B = 3/1.
We know that kinetic energy (KE) is given by the formula KE = (1/2)mv^2, where m is the mass and v is the velocity.
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