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A gas undergoes isothermal expansion from 30dm3 to 45dm3 find heat absorbed by gas if external pressure is 10kpa?

Question

A gas undergoes isothermal expansion from 30 dm<sup>3</sup> to 45 dm<sup>3</sup> find heat absorbed by gas if external pressure is 10 kPa?

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Solution

To solve this problem, we need to use the formula for work done during an isothermal expansion, which is W = PΔV, where P is the pressure and ΔV is the change in volume.

Step 1: Convert the pressure from kPa to Pa. 1 kPa = 1000 Pa. So, 10 kPa = 10,000 Pa.

Step 2: Convert the volumes from dm^3 to m^3. 1 dm^3 = 0.001 m^3. So, 30 dm^3 = 0.03 m^3 and 45 dm^3 = 0.045 m^3.

Step 3: Calculate the change in volume. ΔV = V_final - V_initial = 0.045 m^3 - 0.03 m^3 = 0.015 m^3.

Step 4: Substitute the values into the formula for work done. W = PΔV = 10,000 Pa * 0.015 m^3 = 150 J.

In an isothermal process, the heat absorbed by the gas is equal to the work done on the gas. Therefore, the heat absorbed by the gas is 150 J.

This problem has been solved

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