If one of the zeroes of the quadratic polynomial (k – 1)x2 + kx + 1 is –3, then the value of k isSelect an answerA4/3B– 4/3C2/3D– 2/3
Question
Solution 1
The given quadratic polynomial is (k – 1)x² + kx + 1.
We know that if -3 is a root of the polynomial, then by substituting x = -3 in the polynomial, it should equal to zero.
So, (-3)²(k - 1) + k*(-3) + 1 = 0 => 9(k - 1) - 3k + 1 = 0 => 9k - 9 - 3k + 1 = 0 => 6k - 8 = 0 => 6k = 8 => k = 8/6 = 4/3
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