What will be the output of the given Python code?n=7c=0while(n): if(n > 5): c=c+n-1 n=n-1 else: breakprint(n)print(c)

Question

What will be the output of the given Python code?

n = 7
c = 0
while(n):
    if(n &gt; 5):
        c = c + n - 1
        n = n - 1
    else:
        break
print(n)
print(c)

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Solution

The output of the given Python code will be:

6 6

Here's the step-by-step explanation:

The initial value of n is 7 and c is 0.
The while loop will continue as long as n is not 0.
Inside the loop, it checks if n is greater than 5. If it is, it adds n-1 to c and decreases n by 1. So, in the first iteration, c becomes 6 (7-1) and n becomes 6.
In the next iteration, n is not greater than 5, so it breaks out of the loop.
Finally, it prints the values of n and c, which are 6 and 6 respectively.

This problem has been solved

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