What is the output of the following code?          for i in range(1, 5):if i == 3:    breakprint(i)Answer area1 2 31 21 2 3 41 2 4

Break Down the Problem

1. Identify the loop structure and the condition inside the loop.
2. Determine what happens when the condition is met.
3. Analyze the print statement and what values will be printed before the loop exits.

Relevant Concepts

• The for loop iterates over a specified range.
• The break statement terminates the loop when a condition is met.

Analysis and Detail

1. The for loop starts with i = 1 and goes up to i = 4 (the range is 1 to 5, but 5 is not included).
2. On each iteration, the value of i is checked:
   • i = 1 → print 1
   • i = 2 → print 2
   • i = 3 → the condition if i == 3 is true, so break is executed, and the loop is exited.

Verify and Summarize

The final value of i printed just before the loop exits are 1 and 2. The loop will halt before printing 3.

Final Answer

The output of the code will be:

1
2