The intermediate formed during the addition of HClHCl to propene in the presence of peroxide is
Question
The intermediate formed during the addition of HCl to propene in the presence of peroxide is
Solution
The intermediate formed during the addition of HCl to propene in the presence of peroxide is a carbocation. Here are the steps:
-
The reaction begins with the formation of a free radical on the chlorine atom due to the presence of peroxide. Peroxide is a radical initiator that can break the H-Cl bond homolytically to form two chlorine radicals.
-
The chlorine radical then reacts with the propene molecule. It will preferentially add to the less substituted carbon atom due to its size and reactivity, forming a secondary carbocation. This is known as the Markovnikov rule.
-
Finally, the remaining Cl- ion will react with the carbocation, forming the final product.
So, the intermediate in this reaction is a secondary carbocation.
Similar Questions
The reaction of hydrogen bromide with propene in absence of peroxide is an example of a/an
How do hydrogen peroxide react with enzymes? Show the reaction involved. Why is there no reaction in other samples?
When alkyl substituted acetylene undergoes addition with hydrogen in presence of Lindlar’s catalyst, the alkene formed is
Write hydrocarbon radicals that can be formed as intermediates during monochlorinationof 2-methylpropane? Which of them is more stable? Give reasons
The number of acidic radicals which give colourless gas or fumes when treated with dil. HCl on heating isS2–, , , CH3COO–, , , Cl–, Br–
Upgrade your grade with Knowee
Get personalized homework help. Review tough concepts in more detail, or go deeper into your topic by exploring other relevant questions.