The pH of a solution is defined as the negative logarithm (base 10) of the hydrogen ion concentration, [H+]. This relationship can be written as:

pH = -log[H+]

We can rearrange this equation to solve for [H+]:

[H+] = 10^(-pH)

Given that the pH of the coke is 2.8, we can substitute this value into the equation:

[H+] = 10^(-2.8)

Therefore, the [H+] of the coke at that instant is approximately 1.58 x 10^-3 M.

Question

The pH of a solution is defined as the negative logarithm (base 10) of the hydrogen ion concentration, [H+]. This relationship can be written as:

pH = -log[H+]

We can rearrange this equation to solve for [H+]:

[H+] = 10^(-pH)

Given that the pH of the coke is 2.8, we can substitute this value into the equation:

[H+] = 10^(-2.8)

Therefore, the [H+] of the coke at that instant is approximately 1.58 x 10^-3 M.

Knowee AI · Accepted Answer

The pH of a solution is defined as the negative logarithm (base 10) of the hydrogen ion concentration, [H+]. This relationship can be written as:

pH = -log[H+]

We can rearrange this equation to solve for [H+]:

[H+] = 10^(-pH)

Given that the pH of the coke is 2.8, we can substitute this value into the equation:

[H+] = 10^(-2.8)

Therefore, the [H+] of the coke at that instant is approximately 1.58 x 10^-3 M.

Consider the pH of a can of freshly opened coke is at 2.8, what is the [𝐻+] at that instant?