You have a context-free grammar (CFG) defined as follows:S → aSbS → εWhich of the following strings is generated by this CFG?1 point"aabbb""aaabb""ab""bbb"

The string "ab" is generated by this CFG.

Here's the step-by-step derivation:

1. Start with the start symbol S.
2. Apply the rule S → aSb. Now you have "aSb".
3. Apply the rule S → ε (which means replace S with nothing). Now you have "ab".

The other strings cannot be generated by this CFG. For example, "aabbb" would require two 'a's to be followed by three 'b's, but the CFG only allows for one 'a' to be followed by one 'b'. Similarly, "aaabb" and "bbb" cannot be generated because the number of 'a's and 'b's do not match as required by the CFG.