Given grammar G:S->aS| ABA-> eB-> eD-> bReduce the grammar, removing all the e productions:
Question
Given grammar G:
S -> aS | A
A -> e
B -> e
D -> b
Reduce the grammar, removing all the e productions:
Solution
The given grammar is:
G: S -> aS | ABA
A -> e
B -> e
D -> b
The first step in removing the e productions (also known as epsilon productions) is to identify the nullable variables. A nullable variable is a variable that can generate the empty string. In this case, A and B are nullable variables because they both produce e.
Next, we need to modify the grammar by removing the e productions and adding new productions for each combination of nullable variables in the right-hand side of the original productions.
The modified grammar is:
G: S -> aS | aA | aB | a | ABA | AB | AA | A | BA | B | A |
A ->
B ->
D -> b
In the new grammar, we have removed the e productions and added new productions for each combination of nullable variables in the right-hand side of the original productions. For example, the original production S -> aS has been replaced with four new productions: S -> aS, S -> aA, S -> aB, and S -> a. This is because S could be replaced with any combination of A and B, which are both nullable variables.
Finally, we remove any productions that have become useless. In this case, the productions A -> and B -> are useless because they do not produce any terminals, so we can remove them. The final grammar is:
G: S -> aS | aA | aB | a | ABA | AB | AA | A | BA | B | A |
D -> b
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