Sure, here is the step by step solution:

1. A regular deck of playing cards has 52 cards in total, with 4 of them being kings.

2. The probability of drawing a king on the first draw is 4 out of 52 (since there are 4 kings in a deck of 52 cards). This can be simplified to 1/13.

3. If we do not replace the first card (which is a king), there are now 51 cards left in the deck, with 3 of them being kings.

4. The probability of drawing a king on the second draw is therefore 3 out of 51. This can be simplified to approximately 1/17.

5. The probability of both events happening (drawing a king on the first draw AND drawing a king on the second draw) is the product of the probabilities of each event.

6. Therefore, the probability that both cards drawn are kings (without replacement) is (1/13) * (1/17) = 1/221, or approximately 0.00452 when rounded to five decimal places.

Question

Sure, here is the step by step solution:

1. A regular deck of playing cards has 52 cards in total, with 4 of them being kings.

2. The probability of drawing a king on the first draw is 4 out of 52 (since there are 4 kings in a deck of 52 cards). This can be simplified to 1/13.

3. If we do not replace the first card (which is a king), there are now 51 cards left in the deck, with 3 of them being kings.

4. The probability of drawing a king on the second draw is therefore 3 out of 51. This can be simplified to approximately 1/17.

5. The probability of both events happening (drawing a king on the first draw AND drawing a king on the second draw) is the product of the probabilities of each event.

6. Therefore, the probability that both cards drawn are kings (without replacement) is (1/13) * (1/17) = 1/221, or approximately 0.00452 when rounded to five decimal places.

Knowee AI · Accepted Answer

Sure, here is the step by step solution:

1. A regular deck of playing cards has 52 cards in total, with 4 of them being kings.

2. The probability of drawing a king on the first draw is 4 out of 52 (since there are 4 kings in a deck of 52 cards). This can be simplified to 1/13.

3. If we do not replace the first card (which is a king), there are now 51 cards left in the deck, with 3 of them being kings.

4. The probability of drawing a king on the second draw is therefore 3 out of 51. This can be simplified to approximately 1/17.

5. The probability of both events happening (drawing a king on the first draw AND drawing a king on the second draw) is the product of the probabilities of each event.

6. Therefore, the probability that both cards drawn are kings (without replacement) is (1/13) * (1/17) = 1/221, or approximately 0.00452 when rounded to five decimal places.

From a pack of regular playing cards, two cards are drawn at random. What is the probability that both cards will be kings, if the card is NOT replaced?

Question

From a pack of regular playing cards, two cards are drawn at random.

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