X Frequency1 580 42Question 1/3MandatoryComprehensionFind the mean and standard deviation of X.
Question
Question 1/3
Mandatory Comprehension
Find the mean and standard deviation of X.
| X | Frequency1 | 580 | 42 |
Solution
To find the mean and standard deviation of X, we need to calculate the sum of the values and the sum of the squared differences from the mean.
Step 1: Calculate the sum of the values. To find the sum of the values, we multiply each value of X by its corresponding frequency and then add them all together. Sum of values = (580 * 42) = 24,360
Step 2: Calculate the mean. The mean is calculated by dividing the sum of the values by the total frequency. Mean = Sum of values / Total frequency = 24,360 / 42 = 580
Step 3: Calculate the sum of the squared differences from the mean. To find the sum of the squared differences from the mean, we subtract the mean from each value of X, square the result, multiply it by the frequency, and then add them all together. Sum of squared differences = [(580 - 580)^2 * 42] = 0
Step 4: Calculate the variance. The variance is calculated by dividing the sum of the squared differences from the mean by the total frequency. Variance = Sum of squared differences / Total frequency = 0 / 42 = 0
Step 5: Calculate the standard deviation. The standard deviation is the square root of the variance. Standard deviation = √(Variance) = √(0) = 0
Therefore, the mean of X is 580 and the standard deviation is 0.
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