In covering a distance of 60 km , Anil takes 2 hours more than Asif. If Anil doubles his speed , then he would take1 hr less than Asif . What is Anil's speed ?

Let's denote the speed of Anil as 'a' km/hr and the speed of Asif as 's' km/hr.

From the problem, we have two equations:

1. 60/a = 60/s + 2 (since Anil takes 2 hours more than Asif to cover the same distance)

2. 60/(2a) = 60/s - 1 (since if Anil doubles his speed, he would take 1 hour less than Asif)

Now, we can solve these equations to find the value of 'a' (Anil's speed).

First, simplify the equations:

1. s = 60/a - 2

2. s = 120/a + 1

Setting the two equations equal to each other gives:

60/a - 2 = 120/a + 1

Solving this equation for 'a' gives:

a^2 - 60a + 120 = 0

This is a quadratic equation in the form of ax^2 + bx + c = 0, where a = 1, b = -60, and c = 120.

We can solve this equation using the quadratic formula, x = [-b ± sqrt(b^2 - 4ac)] / (2a):

a = [60 ± sqrt((-60)^2 - 41120)] / (2*1) a = [60 ± sqrt(3600 - 480)] / 2 a = [60 ± sqrt(3120)] / 2 a = [60 ± 55.901] / 2

We have two possible solutions: a = (60 + 55.901) / 2 = 57.95 km/hr and a = (60 - 55.901) / 2 = 2.049 km/hr.

However, since Anil's speed cannot be greater than Asif's (because he takes more time to cover the same distance), the only feasible solution is a = 2.049 km/hr.

So, Anil's speed is approximately 2.049 km/hr.