A Lossless transmission line of length 50cm with L = 10microH/m, C=40pF/m is operated at 30MHz,its electrical length isSelect one:a. 1.88b. 0.2λc. 108od. 40π

To find the electrical length of the transmission line, we can use the formula:

Electrical length = (2πf√(LC)) * length

Given: Length of the transmission line (l) = 50 cm = 0.5 m Inductance per unit length (L) = 10 μH/m Capacitance per unit length (C) = 40 pF/m Operating frequency (f) = 30 MHz = 30 * 10^6 Hz

Substituting these values into the formula, we get:

Electrical length = (2π * 30 * 10^6 * √(10 * 10^-6 * 40 * 10^-12)) * 0.5

Simplifying the expression inside the square root:

√(10 * 10^-6 * 40 * 10^-12) = √(400 * 10^-18) = √(4 * 10^-16) = 2 * 10^-8

Substituting this value back into the formula:

Electrical length = (2π * 30 * 10^6 * 2 * 10^-8) * 0.5

Simplifying further:

Electrical length = (2π * 30 * 2) * 10^-2

Electrical length = 120π * 10^-2

Therefore, the electrical length of the transmission line is 1.2π.