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A can finish a work in 24 days, B in 9 days and C in 12 days. B & C start the work but are forced to leave after 3 days. The remaining work done by A in:

Question

A can finish a work in 24 days, B in 9 days and C in 12 days. B & C start the work but are forced to leave after 3 days. The remaining work done by A in:

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Solution

Sure, let's solve this step by step:

  1. First, we need to find out the one day work of A, B, and C. A's one day work = 1/24 B's one day work = 1/9 C's one day work = 1/12

  2. B and C worked together for 3 days. So, their combined 3 days work = 3 * (B's one day work + C's one day work) = 3 * ((1/9) + (1/12)) = 1/4

  3. The remaining work after B and C left = 1 - (B and C's 3 days work) = 1 - 1/4 = 3/4

  4. Now, this remaining work is done by A. So, the time taken by A to finish the remaining work = Remaining work / A's one day work = (3/4) / (1/24) = 18 days

So, A will take 18 days to finish the remaining work.

This problem has been solved

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