An object of size 3 cm is placed at a distance of 15 cm from a convex lens. Focallength of lens is 10 cm. Find the position, nature and size of image.

Sure, let's solve this step by step using the lens formula and magnification formula.

1. Lens Formula: 1/f = 1/v - 1/u Where: f = focal length of the lens v = image distance u = object distance

Given: f = 10 cm (convex lens so it's positive) u = -15 cm (object is on the same side as the light source, so it's negative)

We can substitute these values into the lens formula to find v:

1/v = 1/f + 1/u 1/v = 1/10 + 1/(-15) 1/v = (15 - 10) / (10 * 15) 1/v = 5 / 150 1/v = 1/30

So, v = 30 cm. The image is formed on the opposite side of the light source, so the image is real and inverted.

2. Magnification (m) Formula: m = -v/u Substitute the values of v and u into the formula:

m = -v/u m = -30 / -15 m = 2

The magnification is 2, which means the image is twice the size of the object.

3. To find the size of the image, we multiply the size of the object by the magnification:

Size of image = object size * magnification Size of image = 3 cm * 2 Size of image = 6 cm

So, the image is 6 cm in size, it is real, inverted and located 30 cm from the lens on the opposite side of the light source.