If the pressure exerted by a gas at 25oC in a volume of 0.044 L is 3.81 atm, how many moles of gas are present?A.0.055 molB.0.0069 molC.0.0062 molD.0.62 mol
Question
If the pressure exerted by a gas at 25°C in a volume of 0.044 L is 3.81 atm, how many moles of gas are present?
A. 0.055 mol
B. 0.0069 mol
C. 0.0062 mol
D. 0.62 mol
Solution
To solve this problem, we can use the ideal gas law equation, which is PV = nRT.
Where: P = pressure V = volume n = number of moles R = ideal gas constant T = temperature
Given in the problem: P = 3.81 atm V = 0.044 L T = 25°C = 298.15 K (converted from Celsius to Kelvin by adding 273.15) R = 0.0821 L.atm/K.mol (this is the value of R when pressure is in atm and volume is in liters)
We need to solve for n, the number of moles.
Rearranging the equation to solve for n gives us n = PV/RT.
Substituting the given values into the equation gives us n = (3.81 atm * 0.044 L) / (0.0821 L.atm/K.mol * 298.15 K)
Calculating this gives us n = 0.0069 mol.
So, the correct answer is B. 0.0069 mol.
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