To solve this problem, we can use the ideal gas law equation, which is PV = nRT.

Here,
P = pressure = 200 kPa = 200,000 Pa (since 1 kPa = 1000 Pa)
V = volume = 2.0 dm^3 = 2.0 L (since 1 dm^3 = 1 L)
R = ideal gas constant = 8.314 J/(mol.K)
T = temperature = 30 °C = 303.15 K (since temperature in Kelvin = temperature in °C + 273.15)

We need to find n, which is the amount of gas in moles.

Rearranging the ideal gas law equation to solve for n, we get n = PV/RT.

Substituting the given values into the equation, we get:

n = (200,000 Pa * 2.0 L) / (8.314 J/(mol.K) * 303.15 K)

After performing the calculation, we get n = 0.080 mol.

So, the amount of gas present is approximately 0.080 mol to two significant figures.

Question

To solve this problem, we can use the ideal gas law equation, which is PV = nRT.

Here, 
P = pressure = 200 kPa = 200,000 Pa (since 1 kPa = 1000 Pa)
V = volume = 2.0 dm^3 = 2.0 L (since 1 dm^3 = 1 L)
R = ideal gas constant = 8.314 J/(mol.K)
T = temperature = 30 °C = 303.15 K (since temperature in Kelvin = temperature in °C + 273.15)

We need to find n, which is the amount of gas in moles.

Rearranging the ideal gas law equation to solve for n, we get n = PV/RT.

Substituting the given values into the equation, we get:

n = (200,000 Pa * 2.0 L) / (8.314 J/(mol.K) * 303.15 K)

After performing the calculation, we get n = 0.080 mol.

So, the amount of gas present is approximately 0.080 mol to two significant figures.

Knowee AI · Accepted Answer

To solve this problem, we can use the ideal gas law equation, which is PV = nRT.

Here, 
P = pressure = 200 kPa = 200,000 Pa (since 1 kPa = 1000 Pa)
V = volume = 2.0 dm^3 = 2.0 L (since 1 dm^3 = 1 L)
R = ideal gas constant = 8.314 J/(mol.K)
T = temperature = 30 °C = 303.15 K (since temperature in Kelvin = temperature in °C + 273.15)

We need to find n, which is the amount of gas in moles.

Rearranging the ideal gas law equation to solve for n, we get n = PV/RT.

Substituting the given values into the equation, we get:

n = (200,000 Pa * 2.0 L) / (8.314 J/(mol.K) * 303.15 K)

After performing the calculation, we get n = 0.080 mol.

So, the amount of gas present is approximately 0.080 mol to two significant figures.

A gas has a volume of 2.0 dm3 at a pressure of 200 kPa and 30 ℃. Calculate the amount (in mol) of gas present.Give your answer to two significant figures.

Question

A gas has a volume of 2.0 dm³ at a pressure of 200 kPa and 30 ℃.

Solution

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A gas has a volume of 2.0 dm3 at a pressure of 200 kPa and 30 ℃. Calculate the amount (in mol) of gas present.Give your answer to two significant figures.