The body is projected with same initial velocity for two projectile. Horizontal range of projectiles is same when the angle of projection are:

The horizontal range (R) of a projectile is given by the equation:

R = (v^2/g) * sin(2θ)

where: v = initial velocity g = acceleration due to gravity θ = angle of projection

Given that the horizontal range is the same for two projectiles with the same initial velocity, we can equate the two equations:

(v^2/g) * sin(2θ1) = (v^2/g) * sin(2θ2)

Solving this equation, we find that:

sin(2θ1) = sin(2θ2)

This equation holds true for two angles if they are complementary, i.e., if they add up to 90 degrees. Therefore, the two angles of projection that would give the same horizontal range for the same initial velocity are two angles that are complementary to each other.

In other words, if one angle is θ, the other angle would be 90 - θ.