12345678910#include <stdio.h> int main() { double x = 12.0; if (x == 12) printf("Hi"); else printf("Welcome"); return 0;}
Question
Question
#include <stdio.h>
int main() {
double x = 12.0;
if (x == 12)
printf("Hi");
else
printf("Welcome");
return 0;
}
Solution
The code you've written is in C language. It's a simple program that checks if the value of variable 'x' is equal to 12. If it is, it prints "Hi". If it's not, it prints "Welcome".
Here's a step-by-step explanation:
-
#include <stdio.h>
: This is a preprocessor command that includes the standard input-output library in the program. -
int main() {
: This is the main function where the program execution begins. -
double x = 12.0;
: Here, a variable 'x' of type double is declared and initialized with the value 12.0. -
if (x == 12) printf("Hi");
: This is an if statement that checks if the value of 'x' is equal to 12. If it is, it prints "Hi". -
else printf("Welcome");
: This is the else part of the if-else statement. If the condition in the if statement is not met (i.e., 'x' is not equal to 12), it prints "Welcome". -
return 0;
: This statement ends the main function and returns the value 0. -
}
: This is the closing brace for the main function.
In this case, the output of the program will be "Hi" because the value of 'x' is indeed 12.0.
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