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12345678910#include <stdio.h> int main() { double x = 12.0; if (x == 12) printf("Hi"); else printf("Welcome"); return 0;}

Question

Question

#include &lt;stdio.h&gt;
int main() {
    double x = 12.0;
    if (x == 12)
        printf(&quot;Hi&quot;);
    else
        printf(&quot;Welcome&quot;);
    return 0;
}
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Solution

The code you've written is in C language. It's a simple program that checks if the value of variable 'x' is equal to 12. If it is, it prints "Hi". If it's not, it prints "Welcome".

Here's a step-by-step explanation:

  1. #include <stdio.h>: This is a preprocessor command that includes the standard input-output library in the program.

  2. int main() {: This is the main function where the program execution begins.

  3. double x = 12.0;: Here, a variable 'x' of type double is declared and initialized with the value 12.0.

  4. if (x == 12) printf("Hi");: This is an if statement that checks if the value of 'x' is equal to 12. If it is, it prints "Hi".

  5. else printf("Welcome");: This is the else part of the if-else statement. If the condition in the if statement is not met (i.e., 'x' is not equal to 12), it prints "Welcome".

  6. return 0;: This statement ends the main function and returns the value 0.

  7. }: This is the closing brace for the main function.

In this case, the output of the program will be "Hi" because the value of 'x' is indeed 12.0.

This problem has been solved

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