In the given figure, PQ = 24 cm, QR = 26 cm ∠PAR = 90°, PA = 6 cm, and AR = 8 cm, the degree measure of ∠QPR is

The problem seems to be a geometry problem involving triangles. However, without the figure, it's hard to visualize the problem. But based on the given information, it seems like we have two right triangles here: Triangle PAR and Triangle QPR.

Here are the steps to solve the problem:

1. Since Triangle PAR is a right triangle with PA = 6 cm and AR = 8 cm, it's a 3-4-5 right triangle (since 6 and 8 are multiples of 3 and 4, respectively). This means ∠PAR = 90°, ∠PRA = 53.13° (arctan(4/3)), and ∠RAP = 36.87° (180° - 90° - 53.13°).

2. Now, let's look at Triangle QPR. We know that ∠QRP = ∠PRA = 53.13° (since they are corresponding angles).

3. To find ∠QPR, we subtract ∠QRP from 180° (since the sum of angles in a triangle is 180°). So, ∠QPR = 180° - 90° - 53.13° = 36.87°.

So, the degree measure of ∠QPR is 36.87°.