In the triangle below, suppose that =m∠I+x2°, =m∠J−4x6°, and =m∠K3x°.Find the degree measure of each angle in the triangle.JIK−4x6°+x2°3x°m∠I = °m∠J = °m∠K = °
Question
In the triangle below, suppose that
=m∠I + x 2°,
=m∠J − 4 x 6°,
and = m∠K 3 x°.
Find the degree measure of each angle in the triangle.
JIK − 4 x 6° + x 2° 3 x°
m∠I = °
m∠J = °
m∠K = °
Solution
The problem seems to be missing some information, but I'll try to explain the general approach to solve this kind of problem.
Step 1: Understand the problem We have a triangle with angles I, J, and K. The measure of each angle is given in terms of a variable x. We need to find the degree measure of each angle.
Step 2: Set up the equation The sum of the angles in a triangle is always 180 degrees. So, we can set up the following equation:
m∠I + m∠J + m∠K = 180°
Substitute the given expressions for each angle:
(x/2)° + (−4x/6)° + 3x° = 180°
Step 3: Solve the equation First, simplify the equation by multiplying each term by the common denominator to get rid of the fractions. Then, solve for x.
Step 4: Substitute x back into the expressions for each angle Once you have the value of x, substitute it back into the expressions for m∠I, m∠J, and m∠K to find the degree measure of each angle.
Please provide the correct expressions for the angles so I can help you solve the problem.
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