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The points of inflexion of the normal curve( )2- t-101 32f(t) = e4 2π are(a) 6, 14(b) 5,15(c) 4,16(d) none of these

Question

The points of inflexion of the normal curve( )2- t-101 32f(t) = e4 2π are(a) 6, 14(b) 5,15(c) 4,16(d) none of these
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Solution 1

The given function is a normal distribution function, which is given by:

f(t) = (1/√(2πσ^2)) * e^(-(t-μ)^2 / 2σ^2)

where μ is the mean and σ is the standard deviation.

The points of inflection of the normal curve are at μ - σ and μ + σ.

Given that the function is f(t) = e^((t-10)^2 / 32) / √(4π) Knowee AI is a powerful AI-powered study tool designed to help you to solve study problem.

Knowee AI  is a powerful AI-powered study tool designed to help you to solve study problem.
Knowee AI  is a powerful AI-powered study tool designed to help you to solve study problem.
Knowee AI  is a powerful AI-powered study tool designed to help you to solve study problem.
Knowee AI  is a powerful AI-powered study tool designed to help you to solve study problem.
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