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Wheel of an engine rotates with an angular speed of 120 rev/min. If radius of the wheel is 2 m, then linear speed ofany point on its rim i

Question

Wheel of an engine rotates with an angular speed of 120 rev/min.

If radius of the wheel is 2 m, then linear speed of any point on its rim is...

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Solution

The linear speed of any point on the rim of the wheel can be calculated using the formula:

v = ω * r

where: v is the linear speed, ω is the angular speed, and r is the radius of the wheel.

However, the angular speed is given in revolutions per minute, so we first need to convert this to radians per second, since the standard unit of angular speed in this formula is rad/s.

1 revolution is equal to 2π radians, and 1 minute is equal to 60 seconds, so:

ω = 120 rev/min * (2π rad / 1 rev) * (1 min / 60 s) = 4π rad/s

Now we can substitute ω and r into the formula:

v = ω * r = 4π rad/s * 2 m = 8π m/s

So, the linear speed of any point on the rim of the wheel is 8π meters per second.

This problem has been solved

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