The statement is **True**.

### Explanation
According to Coulomb's law, the electric field $ E $ created by a point charge $ Q $ is given by the formula:

$$
E = \frac{k \cdot Q}{r^2}
$$

where:
- $ E $ is the electric field strength,
- $ k $ is the electrostatic constant,
- $ Q $ is the charge of the object,
- $ r $ is the distance from the charge.

If the charge $ Q $ is doubled (i.e., changed to $ 2Q $), the new electric field strength $ E' $ can be expressed as:

$$
E' = \frac{k \cdot (2Q)}{r^2} = 2 \cdot \frac{k \cdot Q}{r^2} = 2E
$$

Thus, the electric field strength does indeed increase by a factor of 2.

Question

The statement is **True**.

### Explanation
According to Coulomb's law, the electric field $ E $ created by a point charge $ Q $ is given by the formula:

$$
E = \frac{k \cdot Q}{r^2}
$$

where:
- $ E $ is the electric field strength,
- $ k $ is the electrostatic constant,
- $ Q $ is the charge of the object,
- $ r $ is the distance from the charge.

If the charge $ Q $ is doubled (i.e., changed to $ 2Q $), the new electric field strength $ E' $ can be expressed as:

$$
E' = \frac{k \cdot (2Q)}{r^2} = 2 \cdot \frac{k \cdot Q}{r^2} = 2E
$$

Thus, the electric field strength does indeed increase by a factor of 2.

Knowee AI · Accepted Answer

The statement is **True**.

### Explanation
According to Coulomb's law, the electric field $ E $ created by a point charge $ Q $ is given by the formula:

$$
E = \frac{k \cdot Q}{r^2}
$$

where:
- $ E $ is the electric field strength,
- $ k $ is the electrostatic constant,
- $ Q $ is the charge of the object,
- $ r $ is the distance from the charge.

If the charge $ Q $ is doubled (i.e., changed to $ 2Q $), the new electric field strength $ E' $ can be expressed as:

$$
E' = \frac{k \cdot (2Q)}{r^2} = 2 \cdot \frac{k \cdot Q}{r^2} = 2E
$$

Thus, the electric field strength does indeed increase by a factor of 2.

As the charge of Object A is doubled, the electric field strength created by object A increases by a factor of 2.Group of answer choicesTrueFalse

Question

As the charge of Object A is doubled, the electric field strength created by object A increases by a factor of 2.

Solution

Explanation

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