Find the equation of the line that passes through the following two points:(4, -27) and (8, -51)
Question
Find the equation of the line that passes through the following two points:
(4, -27)
and
(8, -51)
Solution
Step 1: Find the slope (m) of the line. The formula to find the slope between two points (x1, y1) and (x2, y2) is (y2 - y1) / (x2 - x1).
Using the given points (4, -27) and (8, -51), the slope m = (-51 - (-27)) / (8 - 4) = -24 / 4 = -6.
Step 2: Use the point-slope form of a line equation, y - y1 = m(x - x1), where m is the slope and (x1, y1) is a point on the line.
Using the slope -6 and the point (4, -27), the equation becomes y - (-27) = -6(x - 4).
Step 3: Simplify the equation.
y + 27 = -6x + 24.
Step 4: Rearrange the equation to the slope-intercept form, y = mx + b.
y = -6x + 24 - 27.
So, the equation of the line that passes through the points (4, -27) and (8, -51) is y = -6x - 3.
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