Prove that a quantum channel NA→B is entanglement-breaking if (idR ⊗NA→B ) (ΦRA)is a separable state, where ΦRA is a maximally entangled state
Question
Prove that a quantum channel is entanglement-breaking if is a separable state, where is a maximally entangled state
Solution
To prove that a quantum channel NA→B is entanglement-breaking if (idR ⊗NA→B ) (ΦRA) is a separable state, where ΦRA is a maximally entangled state, we can follow these steps:
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Definition: A quantum channel NA→B is called entanglement-breaking if for any system R and any state ρRA, the state (idR ⊗NA→B ) (ρRA) is separable.
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Given: We are given that (idR ⊗NA→B ) (ΦRA) is a separable state, where ΦRA is a maximally entangled state.
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Maximally Entangled State: A maximally entangled state is a state that is maximally entangled if it is as entangled as possible. This means that it cannot be transformed into another state by local operations and classical communication (LOCC).
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Separable State: A state is separable if it can be written as a convex combination of product states.
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Proof: To prove that NA→B is entanglement-breaking, we need to show that for any system R and any state ρRA, the state (idR ⊗NA→B ) (ρRA) is separable.
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Since we are given that (idR ⊗NA→B ) (ΦRA) is a separable state, where ΦRA is a maximally entangled state, this means that the quantum channel NA→B has the property that it transforms a maximally entangled state into a separable state.
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Therefore, by definition, the quantum channel NA→B is entanglement-breaking.
This is a high-level proof and the actual mathematical proof would involve more detailed calculations and manipulations of the quantum states and channels.
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