Determine the equivalent capacitance of three capacitors, C1=10 pF, C2= 14 pF, C3 = 20 pFthat are connected in series in a circuit
Question
Determine the equivalent capacitance of three capacitors,
C1 = 10 pF,
C2 = 14 pF,
C3 = 20 pF
that are connected in series in a circuit.
Solution
When capacitors are connected in series, the total or equivalent capacitance (Ceq) is given by the reciprocal of the sum of the reciprocals of the individual capacitances.
The formula is:
1/Ceq = 1/C1 + 1/C2 + 1/C3
Substituting the given values:
1/Ceq = 1/10 + 1/14 + 1/20
To simplify this, you can add the fractions:
1/Ceq = 0.1 + 0.0714 + 0.05
1/Ceq = 0.2214
To find Ceq, take the reciprocal of the sum:
Ceq = 1 / 0.2214
Ceq = 4.51 pF
So, the equivalent capacitance of the three capacitors connected in series is approximately 4.51 pF.
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