What is the total capacitance of three capacitors connected in parallel with values of 2.2 μF, 6 μF and 3.2 μF?
Question
What is the total capacitance of three capacitors connected in parallel with values of 2.2 μF, 6 μF and 3.2 μF?
Solution
When capacitors are connected in parallel, the total capacitance (C_total) is simply the sum of the individual capacitances.
Here are the steps to calculate the total capacitance:
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Identify the capacitance of each capacitor. In this case, the capacitors have capacitances of 2.2 μF, 6 μF, and 3.2 μF.
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Add the capacitances together to calculate the total capacitance.
C_total = C1 + C2 + C3 C_total = 2.2 μF + 6 μF + 3.2 μF C_total = 11.4 μF
Therefore, the total capacitance of the three capacitors connected in parallel is 11.4 μF.
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