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The magnetic flux linked with a coil changes by 2×10-2Wb when the currentchanges by 0.01A. The self inductance of the coil is

Question

The magnetic flux linked with a coil changes by 2×10<sup>-2</sup> Wb when the current changes by 0.01 A. The self inductance of the coil is

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Solution

The self-inductance of a coil is defined as the ratio of the magnetic flux to the current. It is given by the formula:

L = ΔΦ/ΔI

where: L is the self-inductance, ΔΦ is the change in magnetic flux, and ΔI is the change in current.

Given that ΔΦ = 2×10^-2 Wb and ΔI = 0.01 A, we can substitute these values into the formula to find the self-inductance:

L = (2×10^-2 Wb) / (0.01 A) = 2 H

So, the self-inductance of the coil is 2 Henry.

This problem has been solved

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