The current in a coil decreases from 30 amp to 10 amp in 0.2 sec if the self inductance of coil is 4 Henry. What is the induced emf in volts?
Question
The current in a coil decreases from 30 amp to 10 amp in 0.2 sec if the self inductance of coil is 4 Henry. What is the induced emf in volts?
Solution
To find the induced emf, we can use Faraday's law of electromagnetic induction, which states that the induced emf is equal to the rate of change of magnetic flux. In mathematical terms, it is given by:
E = -L * (ΔI/Δt)
where: E is the induced emf, L is the self-inductance of the coil, ΔI is the change in current, and Δt is the change in time.
Given in the problem: L = 4 Henry, ΔI = Final current - Initial current = 10 Amp - 30 Amp = -20 Amp (The negative sign indicates that the current is decreasing), Δt = 0.2 sec.
Substituting these values into the formula, we get:
E = -4 Henry * (-20 Amp / 0.2 sec) = 400 Volts.
So, the induced emf is 400 Volts.
Similar Questions
The current in a coil of inductance 5H decreases at the rate of 2A/s. The induced e.m.f is
A steady current is passing through a coil, magnitude of self- induced emf in it,will be:A. zero ⃝ B. maximum
When the current changes from +2 A to - 2 A in 0.05s, and EMF of 8V is inducted in a coil. The coefficient of self-induction of the coil is
The magnetic flux linked with a coil changes by 2×10-2Wb when the currentchanges by 0.01A. The self inductance of the coil is
A coil induces 350 mV when the current changes at the rate of 1 A/s. The value of inductance is:a.350mHb.250mHc.150mHd.3,500mH
Upgrade your grade with Knowee
Get personalized homework help. Review tough concepts in more detail, or go deeper into your topic by exploring other relevant questions.