When factoring the following expression, 2(9c2 - 49d2) to the simplest factored form, how many binomials will you have?

Question

When factoring the following expression, 2(9c² - 49d²) to the simplest factored form, how many binomials will you have?

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Solution

To factor the given expression, 2(9c^2 - 49d^2), you first need to recognize that it is a difference of squares. The difference of squares is a special case in factoring and it follows the pattern: a^2 - b^2 = (a - b)(a + b).

Step 1: Identify a^2 and b^2 in the expression. Here, a^2 = 9c^2 and b^2 = 49d^2. So, a = 3c and b = 7d.

Step 2: Apply the difference of squares formula. So, 2(9c^2 - 49d^2) = 2[(3c - 7d)(3c + 7d)].

Therefore, the simplest factored form of the expression is 2(3c - 7d)(3c + 7d).

So, you will have two binomials, which are (3c - 7d) and (3c + 7d).

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When factoring the following expression, 2(9c2 - 49d2) to the simplest factored form, how many binomials will you have?

Question

When factoring the following expression, 2(9c² - 49d²) to the simplest factored form, how many binomials will you have?

Solution

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